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3a^2-9a-79=11-a^2
We move all terms to the left:
3a^2-9a-79-(11-a^2)=0
We get rid of parentheses
3a^2+a^2-9a-11-79=0
We add all the numbers together, and all the variables
4a^2-9a-90=0
a = 4; b = -9; c = -90;
Δ = b2-4ac
Δ = -92-4·4·(-90)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-39}{2*4}=\frac{-30}{8} =-3+3/4 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+39}{2*4}=\frac{48}{8} =6 $
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